Super Drives

Importing in iTunes does in fact relate to that many times faster than listening speed.

However data transfer rates on optical drives (48x etc) is not the same thing - it relates to how many kbps.

A DVD at 4x is, if I remember correctly, roughly a CD at 24x.
 
Yep -- a CD-ROM at normal 1x speed transfers data at 150kbps. Just factor in the speed of the drive, and you'll have a theoretical maximum ripping speed (for example, a CD-ROM that rips at 52x should have a maximum theoretical ripping speed of 7800kbps, but you'll probably never get that).

A DVD-ROM at normal 1x speed transfers data at 1250kbps, so an 8x DVD drive should have a theoretical maximum ripping speed of 10000kbps.

Just a difference in data transfer rates -- CD-ROMs at 1x transfer 150kbps, while DVD-ROMs at 1x transfer 1250kbps.

A DVD at 4x transfers data as fast as a CD-ROM does at 33.3x (about 5000kbps).
 
Ok.. so what is the required drive-speed for a CD to play at normal speed?

i mean, they didn't just say "let's grab a number, and that wil be 1x, no matter how fast it needs to be to read the CDDA data"
 
1x CD = minimum for CD audio playback. That's what the original CD players operated at, which is why it the base of the system. Same for DVDs, i.e., 1x DVD = minimum for DVD playback.
 
However data transfer rates on optical drives (48x etc) is not the same thing - it relates to how many kbps.
Click to expand...

so this is actually incorrect? if 1x CD (data-rate) == 1x real-time then surely 48x data rate == 48x real-time???
 
Yes, that's correct, but it's almost impossible for a CD-ROM drive to achieve a 48x data transfer rate, even though the CD-ROM says that it can go that fast. This is due to the fact that CDs aren't perfect (they're not perfectly balanced) and that this theoretical maximum is only achievable on the very outer edge of the disk, where the disk is "spinning faster (so to speak)."
 
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